which explains how to find the radius of a circle whose equation is in the form x2 + y2 = z?
Which explains how to find the radius of a circle whose equation is in the form x2 y2 = z?
Answers
If the expression is x^2 + y^2 = z, means that the radius is √z.
That is because the general expression of a circle with the center at the origin of the coordinate system is x^2 + y^2 = (radius)^2
Then in your expression z = (radius)^2, and the radius is found by taking square root>
√(radius)^2 = √z
=>radius = √z
The radius is the square root of the constant term, z.
answer c
Step-by-step explanation:
c
Step-by-step explanation:
C
Step-by-step explanation:
The radius is the square root of the constant term, z.
Find the square root of zdats d radius.
answer = √z.
It depends on what z is
The radius is the square root of the constant term, z
Step-by-step explanation:
makes sense, also took the test :)
z would be your radius
Step-by-step explanation:
Equation: (x - h)² + (y - k)² = r²
Simply take √r² to find r, your radius.
The standard form of the equation for a circle with radius r, centered at (h,k) is
(x - h)^2 + (y - k)^2 = r^2
The given equation is
x^2 + y^2 = z
Therefore h=0, k=0, and the circle has its center at the origin.
The radius is given by
r^2 = z => r =√z
The radius is the square root of the constant term z.
We know that
the equation of a circle is
(x-h)²+(y-k)²=r²
where
(h,k) is the center
and
r is the radius
in the problem
we have
x² + y² = z
so
the center is the origin (0,0)
and the radius r² is z
r²=z> r=√z
the answer is
The radius is the square root of the constant term, z
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which explains how to find the radius of a circle whose equation is in the form x2 + y2 = z?
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